【Proteus仿真】8x8Led点阵数字循环显示

【Proteus仿真】8x8Led点阵数字循环显示


  • Proteus仿真演示
    在这里插入图片描述

8x8点阵取模工具和方法

通过鼠标点亮要显示的方格,然后点击生成数组,将取模好的数组放到程序代码中,至于是共阴还是共阳,可以调试看效果就明白了,如果显示的效果是反的,那就点击切换共阴/共阳按钮即可。

在这里插入图片描述

示例程序代码

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#include <reg52.h>
#include <intrins.h>
#define uchar unsigned char
#define uint unsigned int

uchar code Table_OF_Digits[]=
{

0x00,0x7E,0x81,0x81,0x81,0x81,0x7E,0x00,/\*'0'\*/
0x00,0x00,0x43,0xFF,0xFF,0x03,0x00,0x00,/\*'1'\*/
0x00,0x00,0x43,0xFF,0xFF,0x03,0x00,0x00,/\*'2'\*/
0x00,0x99,0x99,0x99,0x99,0xFF,0xFF,0x00,/\*'3'\*/
0x00,0x0c,0x14,0x24,0x7f,0x04,0x00,0x00,
0x00,0x72,0x51,0x51,0x51,0x4e,0x00,0x00,
0x00,0x3e,0x49,0x49,0x49,0x26,0x00,0x00,
0x00,0x40,0x40,0x40,0x4f,0x70,0x00,0x00,
0x00,0x36,0x49,0x49,0x49,0x36,0x00,0x00,
0x00,0x32,0x49,0x49,0x49,0x3e,0x00,0x00,
};
uchar i=0,t=0,Num_Index = 0;

void main()
{
P3 = 0x80;
Num_Index = 0;
TMOD = 0x00;
TH0 = (8192-2000)/32;
TL0 = (8192-2000)%32;
TR0 = 1;
IE = 0x82;
while(1);
}

void LED\_Screen\_Display() interrupt 1
{
TH0 = (8192-2000)/32;
TL0 = (8192-2000)%32;
P3 = \_crol\_(P3,1);
P0 = ~Table_OF_Digits[Num_Index \* 8 +i];
if(++i == 8) i = 0;
if(++t == 250)
{
t = 0x00;
if(++Num_Index == 10) Num_Index = 0;
}
}

仿真资源和程序代码(包含取模工具)

本示例基于Proteus8.12平台。

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链接:https://pan.baidu.com/s/1zmGaHUnvJ38W8MtaFht4ig 
提取码:nvax


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